How to find out the
min & max form an unsorted array
Logic:
Suppose an Array value
11,1,23,13,7
Step 1:
Put array first value
in min and max variable
Min = 11
Max = 11
Step 2:
Through loop compare
min and min value with I variable
If( Min > array index value) then
Min = array index value
Else
Max = array index value
public static string maxAndMin(int[] arr)
{
int
min = arr[0];
int
max = arr[0];
// 11 1 13 25 17
for
(int i = 1; i <= arr.Length -
2; i++)
{
if (arr[i] > max)
{
max = arr[i];
}
else
{
min = arr[i];
}
}
return min +" "
+max;
}
static void Main(string[] args)
{
Console.WriteLine("**********************************************************************");
Console.WriteLine("How to find largest and smallest No in unsorted
array ");
Console.WriteLine("**********************************************************************");
Console.WriteLine("Enter the size of array");
int
ArraySize= Convert.ToInt32(Console.ReadLine());
Console.WriteLine("Enter the array element");
int[]
arr = new int[ArraySize];
for
(int i = 0; i<= ArraySize - 1;
i++)
{
arr[i]= Convert.ToInt32(Console.ReadLine());
}
Console.WriteLine(" Result
"
+ Program.maxAndMin(arr));
Console.ReadLine();
}
OutPut
**********************************************************************
How to find largest
and smallest No in unsorted array
**********************************************************************
Enter the size of
array
5
Enter the array
element
11
1
13
25
23
Result 1 25
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