Kangaroo jump problem Solution (Hacker Rank)

Kangaroo jump problem Solution (Hacker Rank)

Problem 

Solution 

    static string kangaroo(int x1, int v1, int x2, int v2)

        {

            int kangarro1 = x1 + v1;

            int kangarro2 = x2 + v2;

                while (kangarro1 <= 10000 || kangarro2 >= 10000)

                {

                    if (kangarro1 == kangarro2)

                    {

                        return "YES";

                    }

                    kangarro1 = kangarro1 + v1;

                    kangarro2 = kangarro2 + v2;

                }

                return "NO";

        }

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Grading Students - Hacker Rank Solution

At HackerLand University, a passing grade is any grade 40 points or higher on a 100 point scale. Sam is a professor at the university and likes to round each student’s grade according to the following rules:

·         If the difference between the grade and the next higher multiple of 5 is less than 3, round to the next higher multiple of 5

·         If the grade is less than 38, don’t bother as it’s still a failing grade

Automate the rounding process then round a list of grades and print the results.

Input Format

The first line contains a single integer denoting  (the number of students).
Each line  of the  subsequent lines contains a single integer, , denoting student 's grade.

Solution in C#

public static List<int> gradingStudents(List<int> grades) { List<int> Newgrades = new List<int>(); foreach (int item in grades) { int val = item; int next5mul = 0; int Valu1 = 0; int i = 1; while (item >= next5mul) { next5mul = i * 5; i++; } if (next5mul - item < 3) { Newgrades.Add(next5mul); } else { Newgrades.Add(item); } } return Newgrades; }

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