How to
remove Duplicate Value from an Array
Array
7
|
8
|
6
|
1
|
1
|
3
|
2
|
2
|
7
|
6
|
3
|
8
|
7
|
Above is Unsorted Array
Output Should be
1
|
2
|
3
|
6
|
7
|
8
|
Solution
Step 1: You have Unsorted Array, Now sort the Array
Step 2: You can use Array.Sort(Name of
Array ) method to sort the array / or simply by code
1
|
1
|
2
|
2
|
3
|
3
|
6
|
6
|
7
|
7
|
7
|
8
|
8
|
Step 3 : Take a Temp Array to store the distinct value in
array
The logic behind the find distinct value is
Check pointed value to next
value i.e Array1[1] = 7and Array1[1]= 1and
If both value not equal, then store in new array
1
|
2
|
3
|
6
|
7
|
8
|
int[] array1 = { 7,8,6,1,1,3,2,2,7,6,3,8,7 };
Array.Sort(array1);
array1.Reverse();
int[] NewArr = new int[array1.Length];
int n,j = 0;
for (int i = 0; i <= array1.Length - 2; i++)
{
if (array1[i] != array1[i + 1])
{
NewArr[j] = array1[i];
j++;
}
}
NewArr[j] = array1[array1.Length - 1];
for (n = 0; n <= j; n++)
{
Console.WriteLine("New array " + NewArr[n]);
}
Console.ReadLine();
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